From: Gunther Diemant <g.diemant@...>
Date: 2011-12-09T01:56:58+09:00
Subject: Re: Removing a multiple array layer

Try prod = prod.product(ranges) without loop.


2011/12/8 Sébastien M. <stkfdt@gmail.com>:
> Hi,
>
> I'm trying to remove a array layer implied by multiple Array#product
>
> Here is the code
> ----------------
> def calculate ranges
>  prod = ranges.shift
>  ranges.each { |r| prod = prod.product(r) }
>  puts prod.to_s
> end
> ---------------------------------------------
> Here is what i do get
> ----------------------
> [
>  [[["a", "b"], ["e", "f"]], ["i", "j"]],
>  [[["a", "b"], ["e", "f"]], ["k", "l"]],
>  ...
> ]
> -------------------------------------------
> And there is what i wish
> ------------------------
> [
>  [["a", "b"], ["e", "f"], ["i", "j"]],
>  [["a", "b"], ["e", "f"], ["k", "l"]],
>  ...
> ]
>
> Probably a silly question, but it's driving me mad.
> I tried flatten, prod = prod[0], using Array#permutation, ...
> Can't find my way out..???
>
> Thanks
>
> --
> Posted via http://www.ruby-forum.com/.
>