From: David Alan Black <dblack@...>
Date: 2002-04-26T19:52:48+09:00
Subject: Re: Parsing Repeating Regexp Matches

Hello --

On Fri, 26 Apr 2002, Curt Sampson wrote:

> On Fri, 26 Apr 2002, Michael Brailsford wrote:
>
> > >     "{foo} {bar} {something else} {and so on}"
> > >
> > > And I want to parse it into an array that looks like this:
> > >
> > >     ["foo", "bar", "something else", "and so on"]
> >
> > Try String#scan.  It is similar to te g options in sed/vim/perl's s///,
> > and the return from String#scan is an Array.
>
> Ah, that's it. So I want
>
>     parsed_defs = defs.scan(/\{([^}]+)} ?/).collect { |m| m[0] }

You can just .flatten the resulting array of arrays:

     parsed_defs = defs.scan(/\{(.*?)\}/).flatten

Tossing in another possible way to do the regex, just for fun :-)  Also,
you could possibly avoid the need to flatten if you did something like:

   s.scan(/[^{}]+(?=\})/)


David

-- 
David Alan Black
home: dblack@candle.superlink.net
work: blackdav@shu.edu
Web:  http://pirate.shu.edu/~blackdav