From: Cassna Capriet Date: 2011-11-09T06:48:58+09:00 Subject: Re: Building a data structure - Hashes of Hashes of Hashes of Arrays Hi there. Hard to read all your text... Consider to write enough... but not all. You have to declare your variable in this way: a = Hash.new{|h, k| h[k] = Hash.new(&h.default_proc)} So, for example: >> a = Hash.new{|h, k| h[k] = Hash.new(&h.default_proc)} => {} >> b = [1,2,3,4,5] => [1, 2, 3, 4, 5] >> a["2011"]["november"]["tuesday"] = b => [1, 2, 3, 4, 5] >> puts a["2011"]["november"]["tuesday"] 1 2 3 4 5 => nil >> puts a {"2011"=>{"november"=>{"tuesday"=>[1, 2, 3, 4, 5]}}} => nil -- Posted via http://www.ruby-forum.com/.