From: Jeremy Bopp <jeremy@...>
Date: 2011-11-08T13:22:05+09:00
Subject: Re: Why does not this work?

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5/9 is integer division, so it evaluates to 0. That is multiplied with i-32 which also evaluates to 0.

The fix is to force floating point division by using at least one floating point literal in the division operation:

c = (i-32)*(5.0/9)

-Jeremy

Erbay Yigit <erbayyigit@gmail.com> wrote:

Hi guys,
I am trying to learn Ruby. I know some Perl. I cannot make following
script work. Could you please help me understand why "c" value in the
code does not print. It prints "0" for me. Thank you for help.

code:
--------
temp1 = 1
temp2 = 15

puts "F:C"

temp1.upto(temp2) do |i|
c = (i-32)*(5/9)
print i,':',c,"\n"
end
--------

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