From: Harry Kakueki <list.push@...>
Date: 2011-09-05T21:21:06+09:00
Subject: Re: Beginner needing help - Writing right-angle triangle program

>
> And uh, this isn't really programming, but how did you go by getting the
> hypotenuse? I'm a little confused by the code :3. Thanks!
>

p = perimeter
a**2 + b**2 = c**2
b = p-a-c
a**2 + (p-a-c)**2 = c**2
a**2 + p**2 - pa - pc - ap + a**2 + ac - cp + ca + c**2 = c**2
a**2 + (p**2 - 2ap + a**2) - 2c(p-a) = 0
2c(p-a) = a**2 + (p-a)**2
2c = (a**2 + (p-a)**2) / (p-a)
c = (a**2 + (p-a)**2) / 2(p-a)




Harry