From: justincollins@...
Date: 2011-09-01T07:06:39+09:00
Subject: Re: ripper on array access operation

Quoting "Surya G." <sgaddipati@obtiva.com>:

> Ripper.sexp('a[1]')
>
> yeilds the following output
>
>
> [:program, [[:aref, [:var_ref, [:@ident, "a", [1, 0]]],
> [:args_add_block, [[:@int, "1", [1, 2]]], false]]]]
>
>
> i am trying to figure out where the information that the methods :[] was
> called is present.
>
>
> But when i do
>
> Ripper.sexp('a.[](0)')
>
> [:program, [[:method_add_arg, [:call, [:var_ref, [:@ident, "a", [1,
> 0]]], :".", [:@op, "[]", [1, 2]]], [:arg_paren, [:args_add_block,
> [[:@int, "0", [1, 5]]], false]]]]]
>
> I get the information about which method was called.
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

I am pretty sure it's the :aref part. Ripper is making [] a special case.

-Justin