From: Robert Klemme <shortcutter@...>
Date: 2011-08-25T17:32:47+09:00
Subject: Re: how to find all matches using ruby regex?

On Thu, Aug 25, 2011 at 12:14 AM, michael xu <guorong.xu@gmail.com> wrote:
> I have the following ruby code and I want to find all matched
> "data-1.2.5.tar.gz" and "data-1.2.7.tar.gz", then stored in $1 and $2.
> When I executed it and I found $1 is "data-1.2.5.tar.gz", but $2 is nil.
> How can I get $2 is "data-1.2.7.tar.gz"?
>
> =============================================================
> string1 = "data-1.2.5.tar.gz and data-1.2.7.tar.gz and readme."
>
> if string1 =~ /(data-\d+\.\d+\.\d+\.tar\.gz)/
>  print "Matched on ", $1, "\n"
>  print "Matched on ", $2, "\n"
>
> else
>  puts "NO MATCH"
> end

Are you sure there are always exactly two of them?  If not, #scan is better:

irb(main):001:0> string1 = "data-1.2.5.tar.gz and data-1.2.7.tar.gz and readme."
=> "data-1.2.5.tar.gz and data-1.2.7.tar.gz and readme."
irb(main):002:0> string1.scan /data-\d+(?:\.\d+)*\.tar\.gz/
=> ["data-1.2.5.tar.gz", "data-1.2.7.tar.gz"]

Kind regards

robert


-- 
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/