From: "Nik Z." <esperantoca@...>
Date: 2011-08-25T09:19:59+09:00
Subject: Re: how to find all matches using ruby regex?

You never set the 2nd set of parens (...) in the original regex:
(data-\d+\.\d+\.\d+\.tar\.gz)/

therefore, no $2 for you...

change to regex to /(data\S+) and (data\S+)/, and you get $1 and $2...




michael xu wrote in post #1018329:
> I have the following ruby code and I want to find all matched
> "data-1.2.5.tar.gz" and "data-1.2.7.tar.gz", then stored in $1 and $2.
> When I executed it and I found $1 is "data-1.2.5.tar.gz", but $2 is nil.
> How can I get $2 is "data-1.2.7.tar.gz"?
>
> =============================================================
> string1 = "data-1.2.5.tar.gz and data-1.2.7.tar.gz and readme."
>
> if string1 =~ /(data-\d+\.\d+\.\d+\.tar\.gz)/
>   print "Matched on ", $1, "\n"
>   print "Matched on ", $2, "\n"
>
> else
>   puts "NO MATCH"
> end

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