Re: Gritty Details of super()

On Sun, Aug 21, 2011 at 7:48 PM, Gavin Kistner <[e-mail]> wrote:
> On Aug 21, 2011, at 11:21 AM, luke gruber <[e-mail]> wrote:
>
>> But the issue I ran into was calling super in a singleton method of a
>> class object ie: Someclass.somemethod(), and hoping that my included
>> module that also defined a singleton method would catch the call to
>> super().
>
> This isn't related to super so much as it is the nature of inheritance an=
d modules in Ruby. See this diagram:
>
> http://phrogz.net/RubyLibs/RubyMethodLookupFlow.png
>
> If you want inheritance for singleton methods of an object from a module =
you must _extend_ the object with a module defining _instance_ methods.
>
> For example:
>
> module Foo
> =A0def self.included(klass)
> =A0 =A0klass.extend(ClassMethods)
> =A0end
> =A0module ClassMethods
> =A0 =A0def bar; =85; end
> =A0end
> end
>
> class Bar
> =A0include Foo
> end
>
> Bar.bar
>
> (typed on the phone; forgive untested errors)

Direct extending works as well

     1	#!/usr/bin/env ruby
     2=09
     3	module Mod
     4=09
     5	  def who
     6	    "mod"
     7	  end
     8=09
     9	end
    10=09
    11	class Test
    12	  extend Mod
    13=09
    14	  def self.who
    15	    ret =3D super
    16	    [ret, "test"]
    17	  end
    18=09
    19	end
    20=09
    21	p Test.ancestors  # includes Mod
    22	p Test.superclass # is Object!!
    23	p Test.who # DOESN'T WORK

Kind regards

robert


--=20
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/