From: Robert Klemme <shortcutter@...>
Date: 2011-07-25T02:09:33+09:00
Subject: Re: Exclusive operator in ruby

On Sun, Jul 24, 2011 at 5:57 PM, Adam Prescott <adam@aprescott.com> wrote:
> On Sun, Jul 24, 2011 at 11:12 AM, amir e. <aef1370@gmail.com> wrote:
>
>> 2 - As respect , Ruby is very comfort language , can we define function
>> like this :
>> def myFunc( a=0 , b=1 , c=2 )
>> d = a+b+c
>> end
>>
>> and call this function with only third argument like :
>> myFunc( , , 10).
>>
>
> You can if you're using 1.9. This isn't keyword arguments.

Nice!

>>> def x(a = 1, b = 2, c)
>>>   [a, b, c]
>>> end
> => nil
>>> x(2)
> => [1, 2, 2]
>>> x(3)
> => [1, 2, 3]
>>> x(5, 6)
> => [5, 2, 6]
>>> x(15, 20, 25)
> => [15, 20, 25]

The variant with keyword arguments:

irb(main):030:0> def x(ag={})
irb(main):031:1> ag = {a:1,b:2,c:3}.merge ag
irb(main):032:1> [ag[:a], ag[:b], ag[:c]]
irb(main):033:1> end
=> nil
irb(main):034:0> x
=> [1, 2, 3]
irb(main):035:0> x(a:99)
=> [99, 2, 3]
irb(main):036:0> x(c:99)
=> [1, 2, 99]
irb(main):037:0> x(c:99,b:22)
=> [1, 22, 99]

Kind regards

robert

-- 
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/