From: Larry Lv <larrylv1990@...>
Date: 2011-04-22T18:24:27+09:00
Subject: Re: Reversing a string without using array, classes and reverse function

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#!/usr/bin/env ruby

while line = gets.chomp
  r = String.new
  (1..line.length).each do |i|
    r << line[-1*i]
  end
  puts r
  puts r == line.reverse
end

On Fri, Apr 22, 2011 at 4:43 PM, Stu <stu@rubyprogrammer.net> wrote:

> One more with ruby blocks (This would be the ruby way =) )
>
> s = "1234567890"
> r = String.new
> s.length.times{|i| r << s[(i+1)*(-1)]}
>
> r == s.reverse
> true
>
> cheers!!!
>
> That was fun!!!... give me another =)
>
> ~Stu
> On Fri, Apr 22, 2011 at 3:32 AM, Stu <stu@rubyprogrammer.net> wrote:
> > On Fri, Apr 22, 2011 at 2:45 AM, Jose Calderon-Celis
> > <josecalderoncelis@gmail.com> wrote:
> >
> >> for j in 1..len do
> >>  mycommand += s[-1*j]
> >>
> >>
> >
> > very nice I like the use of your math. By multiplying the array index
> > by negative one your sending the index a reverse number while your for
> > loop traverses forward. This is perfect logic.
> >
> > Here is a rewrite with my while loop:
> >
> > s = "1234567890"
> > r=String.new
> > i = 1
> > while i <= s.length
> >  r << s[i*(-1)]
> >  i+=1
> > end
> > printf s
> > "0987654321"
> >  => "0987654321"
> >> y == x.reverse
> > true
> >
>
>


-- 
Best Regards,

*Larry Lv*
@ Baidu NLP

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