From: William Djaja Tjokroaminata <billtj@...>
Date: 2002-04-13T01:38:05+09:00
Subject: Re: How to Make a Method Ineffective Efficiently?

I have implemented the construct using the block, which seems the to be
the best solution for now based on the suggestions.  However, although
this may seem sound from the execution time point of view, does this block
construct consumes a lot of memory?  I will have thousands of the
construct, such as

    debug () {[a, b, c, d, e, f, g, h]}                # line 1
    ....
    debug () {[i, j]}                                  # line 2
    ....
    debug () {[x, y, z, a, b, c, g, k, z, l, t, p]}    # line 10,000

Does Ruby creates memory space for each block?  With function call, I
don't think Ruby will create any additional space, only enough to hold the
variables themselves, which is only a, b, ..., z:

    debug (a, b, c, d, e, f, g, h)
    ....
    debug (i, j)
    ....
    debug (x, y, z, a, b, c, g, k, z, l, t, p)

Regards,

Bill
============================================================================
David Alan Black <dblack@candle.superlink.net> wrote:
>>     def debug ()
>>       if @debugging
>>         data = yield
>>         puts "data = #{data}"
>>         .... # do processing with data[0], data[1], ..., data[n]
>>       end
>>     end
>>
>>     debug () {return a, b, c}
>>
>> This does not work!

> Yeah, I've been bitten by that on occasion.  It returns from the
> yielder, not the yieldee.  You'd need to just put the value you
> want:

>   debug { [a,b,c] }
> David