From: "Eric T." <erictetz@...>
Date: 2011-04-18T09:48:01+09:00
Subject: Re: Telnet "More?"

7stud -- wrote in post #993403:
> Yes, that would be pointless, but where does such a function appear in
> your code?

That would be (I thought) the 'out' lambda, but as Christopher 
explained, print is actually a *method* (not obvious if you don't know 
Ruby), so it makes more sense that a closure is required.

In Lua, for instance, print is a global function, so making a closure 
'function out(...) print(...) end' would be utterly superfluous; 
anything you could pass 'out' to you could just pass 'print' to.

It still strikes me odd that Kernel#print is not static (does it modify 
Kernel state?), or if it *is* static that you can't just pass it as-is 
to anything that requires a callable.

-- 
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