From: Jen <jen.bottom@...>
Date: 2011-03-22T05:33:54+09:00
Subject: Counting values in an array, storing in a hash then making an array of hashes?

Hello,

Apologies but i've run in to another problem while attempting to make a 
sudoku solver that uses basic genetic programming.

This time I'm trying to count how many times each number occures in each 
board (boards stored in @offspring) then store the results in a hash.

I think each hash is being overwritten because the keys are the same, so 
I'm attempting to store an array of hashes.

I think I'm close, but my logic is still a bit off, as the length of my 
array of hashes is 1 but I expect it to be 4, with each element 
containing a hash. 4 is the size of the test population I am using, so 
there are 4 boards in @offspring.

I could have probably done the same thing with an array, but I confused 
myself thinking about it :(

My code so far:

def fitness_check
hashes = Array.new
count = Hash.new 0
#Adds another loop to ensure all elements of offspring are checked 
separetly.
i = 0
#loop through every row of offspring (first to fourth element)
@offspring[i.to_i].each do |r|
#loop through every column of every row
r.each do |c|
#Count the numbers in each column
count[c] += 1
hashes[i] = count
end
end

#Need to stop the values in count getting overwritten by the next 
element in @offspring
puts hashes.inspect
puts hashes.length
end

Thanks in advance for any suggestions.

Jen.