From: Stefano Mioli <stefano.mioli@...>
Date: 2011-03-22T00:36:05+09:00
Subject: Re: Logical OR in Ruby

On 21/03/2011 5.09, Paul Sholtz wrote:
> I'm looking at some source code, to try and understand it.

[snip]

> What I think this code means, is that the value that will be assigned to
> "weight" will be either (a) "weight" (if weight has already been
> assigned) or else (b) if "weight" is presently nil, then the value 100
> will be assigned to "weight" instead.
>
> Is this correct?

Yep, as others told you.

It might be worth pointing out, though, that Ruby might have a different
idea of falsehood compared to other languages you might be used to:

irb(main):001:0> puts "hey" if 0
hey
=> nil
irb(main):002:0> puts "hey" if []
hey
=> nil

In Python 0 and [] would both evaluate to False.

-- 
Stefano