From: pat eyler <pat.eyler@...>
Date: 2011-03-21T13:14:25+09:00
Subject: Re: Logical OR in Ruby

On Sun, Mar 20, 2011 at 10:09 PM, Paul Sholtz <paul.sholtz@gmail.com> wrote:
> I'm looking at some source code, to try and understand it.
>
> There's a variable "weight", and then there's this call:
>
> weight ||= 100
>
> which I take to be equivalent to:
>
> weight = weight || 100
>
> (i.e., performing a logical OR between "weight" and 100).
>
> What I think this code means, is that the value that will be assigned to
> "weight" will be either (a) "weight" (if weight has already been
> assigned) or else (b) if "weight" is presently nil, then the value 100
> will be assigned to "weight" instead.
>
> Is this correct?
>

yes.

Generally, you'll find irb to be very helpful in finding things like this out:

irb(main):001:0> foo ||= 10
=> 10
irb(main):002:0> foo
=> 10
irb(main):003:0> foo ||=100
=> 10
irb(main):004:0> foo
=> 10
irb(main):005:0>


> --
> Posted via http://www.ruby-forum.com/.
>
>



-- 
thanks,
-pate
-------------------------
 Don't judge those who choose to sin differently than you do