From: 7stud -- <bbxx789_05ss@...>
Date: 2011-03-15T07:24:00+09:00
Subject: Re: send() with a block?

Thanks for all the responses.  This may be true:

--
The actual method "send" can take a block, and it passes it to the
method being invoked. If it didn't, it would be impossible to pass a
block to a method when invoking it using send.
--

...but why should a beginner have to figure that out?  You shouldn't 
have to be a meta-programming guru to figure out the docs.  Wouldn't it 
be better if beginners posted:  "I really think the docs are great." 
rather than "beginner: the docs are confusing; expert-response: they are 
clear if you are smart."


Why doesn't this work:

def my_meth(*args)
  yield
  p args
end

my_proc = Proc.new {puts 'hello'}
my_meth(1, 2, 3, &my_proc )  #=>'hello' [1, 2, 3]

obj = Object.new
m = obj.method(my_meth)
m.call([10, 20, 30], &my_proc)  #LocalJumpError at yield line

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