From: Josh Cheek <josh.cheek@...>
Date: 2011-03-14T11:30:57+09:00
Subject: Re: send() with a block?

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On Sat, Mar 12, 2011 at 2:45 PM, 7stud -- <bbxx789_05ss@yahoo.com> wrote:

> Why don't the ruby docs say that send() can take a block?
>
> Kernel.send(:define_method, :my_meth) do |x|
>  puts x
> end
>
> my_meth(10)
>
> --output:--
> 10
>
> At the following link there is nothing saying that send() will accept a
> block:
>
> http://www.ruby-doc.org/core/classes/Object.html#M000999
>
> Whereas, for example, at the following link it states that grep() will
> take a block:
>
> http://www.ruby-doc.org/core/classes/Enumerable.html#M001482
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

It says "Invokes the method identified by symbol, passing it any arguments
specified." A block is an argument, it just gets set into an implicit
location by default, or you can make it explicit, putting it into a Proc
object, by putting &varname on the end of your params list.

I've had difficulty following the code examples in this thread. Here is the
one I think is relevant:

def meth(first, second=12 , *rest, &block)
  [first , second , rest , block]
end

send :meth , 1                # => [1, 12, [], nil]
send :meth , 1 , 2            # => [1, 2, [], nil]
send :meth , 1 , 2 , 3        # => [1, 2, [3], nil]
send :meth , 1 , 2 , 3 do end # => [1, 2, [3], #<Proc:0x00000100868340@-:8>]


You can see, it passes on ordinal arguments, args with default values,
variable lengthed arguments, and yes, also blocks.

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