From: Sam Duncan <sduncan@...>
Date: 2011-03-11T08:06:22+09:00
Subject: Re: problem with compilation

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The input string in parse has to match your regex before output exists, 
however the function will attempt to reverse and return output regardless.

On 11/03/11 11:49, Ma Sz wrote:
> class Hexagrid
>
>      @@grid = [%w{ 0 1 2 3 }, %w{ 4 5 6 7 }, %w{ 8 9 A B }, %w{ C D E F
> }]
>
>      def initialize
>          @stacks = Hash.new
>      end
>
>      def parse( string )
>          while string =~ /^\s*(\S+)\s*\{([^\}]+)\}\s*;?\s*(.*)/
>
>              output = ''
>              stack = @stacks[$1] ||= Hash.new
>              data = stack[:data] ||= Array.new
>              pointer = stack[:pointer] ||= [0,0]
>
>              $2.split(//).each do|c|
>                    if c == '>' then pointer[1] += 1
>                 elsif c == '<' then pointer[1] -= 1
>                 elsif c == 'v' then pointer[0] += 1
>                 elsif c == '^' then pointer[0] -= 1
>                 elsif c == '!' then pointer = [0,0]; data.clear
>                 elsif c == '+' then data.unshift
> @@grid[pointer[0]][pointer[1]]
>                 elsif c == 'o' then output<<  data.join
>                 end
>              end
>              string = $3
>          end
>          return output.reverse
>      end
>
>      def english( string )
>          return parse(string).scan(/.{2}/).collect{|tuple|  tuple.hex.chr
> }.join
>      end
> end
>
> hex = Hexagrid.new
> while not $stdin.eof?
>    puts hex.english(gets)
> end
>    

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