From: Robert Klemme <shortcutter@...>
Date: 2011-03-09T18:30:25+09:00
Subject: Re: Posting XML

On Wednesday, March 9, 2011 10:00:06 AM UTC+1, JesseQA wrote:
> On Mar 9, 12:31 am, Robert Klemme <short...@googlemail.com> wrote:
> > On Wed, Mar 9, 2011 at 9:10 AM, JesseQA <uscen...@gmail.com> wrote:
> > > Hi everyone. A newbie with ruby/xml so I am not sure where my trouble
> > > is with my code. It does not seem to do anything when I run it. Your
> > > help is much appreciated!
> > > Here is my code:
> >
> > > I am trying to post an XML file but it does not seem to do anything.
> >
> > What exactly do you mean by that?  Is it not sent to the server?  Does
> > the server not react on it?
> >
> >
> >
> > > Can someone take a look at this code and tell me if it looks correct?
> > > Thank you!
> >
> > > require 'rubygems'
> > > require 'net/https'
> > > require 'net/http'
> > > require 'uri'
> > > require 'nokogiri'
> >
> > > url = "http://mydomain.com/Will.do?method=ntf"
> > > uri = URI.parse(url)
> >
> > > http = Net::HTTP.new(uri.host, uri.port)
> > > http.use_ssl = true if (uri.scheme == 'https')
> >
> > > f = File.open('my.xml','r')
> > > data = Nokogiri::XML(f)
> > > f.close
> >
> > > headers = {'Content-Type' => 'text/xml'}
> >
> > > resp, body = http.post(uri.path, data.to_xml, headers)
> >
> > Why do you read in the file, convert it to a DOM and then convert it
> > back before sending?  IMHO that would only make sense if you either
> > need to validate the XML or change the structure.

> Thanks for the response Robert.
> Would I be able to post like this?
> 
> resp, body = http.post(uri.path, 'my.xml', headers)

Probably rather

resp, body = http.post(uri.path, File.read('my.xml'), headers)

or

File.open('my.xml', 'r') do |io|
  resp, body = http.post(uri.path, io, headers)
end

Note sure though whether the latter approach would work.  "ri" is your friend.

Cheers

robert