From: Karuppasamy M <samykaruppa@...>
Date: 2011-03-05T09:16:19+09:00
Subject: Re: printing regex results

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try this,

irb(main):001:0> str =3D "aaaDDDbDDDcDDDgHHyHjHJkkjUUh"
=3D> "aaaDDDbDDDcDDDgHHyHjHJkkjUUh"
irb(main):002:0> arr =3D str.scan(/([A-Z]{3}[a-z]{1}[A-Z]{3})/)
=3D> [["DDDbDDD"]]
irb(main):009:0> puts arr[0]
DDDbDDD
=3D> nil

Thanks & Best Regards,
M. Karuppasamy



On Sat, Mar 5, 2011 at 4:46 AM, 7stud -- <bbxx789_05ss@yahoo.com> wrote:

> "I=C3=B1aki Baz Castillo" <ibc@aliax.net> wrote in post #985525:
> > 2011/3/4 New C. <coding25@yahoo.com>:
> >> My code is:
> >>
> >> str =3D "aaaDDDbDDDcDDDgHHyHjHJkkjUUh"
> >> arr =3D str.scan(/([A-Z])\1{2}[a-z]\1{3}/)
> >> print arr
> >>
> >> The match is DDDbDDD but the arr prints only the first letter D.
> >> How do I get it to print the full string ("DDDbDDD")?
> >
> > I don't know why, but using [] rather than #scan does the work:
> >
> > str =3D "aaaDDDbDDDcDDDgHHyHjHJkkjUUh"
> > arr =3D str[ /([A-Z])\1{2}([a-z])\1{3}/ ]
> > print arr
> >
> > =3D> "DDDbDDD"
>
> ...but:
>
> puts arr.class
>
> --output:--
> String
>
> --
> Posted via http://www.ruby-forum.com/.
>

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