From: Michael Edgar <adgar@...>
Date: 2011-03-04T02:46:20+09:00
Subject: Re: What is inject doing here?

I'm pretty sure he's just trying to understand inject's behavior on ranges,
not looking for refactoring advice.

Also, on Ruby 1.9, Kernel#p returns its arguments.

Michael Edgar
adgar@carboni.ca
http://carboni.ca/

On Mar 3, 2011, at 5:42 AM, Adam Prescott wrote:

> On Thu, Mar 3, 2011 at 2:15 AM, Todd Benson <caduceass@gmail.com> wrote:
> 
>> irb(main):002:0> (0..3).inject {|s, i| a = i%2 == 0 ? 1 : -1; p a}
>> -1
>> 1
>> -1
>> => -1
>> 
> 
> Why is this done using inject? s is never used in the block, but since `p a`
> returns nil, s would be nil in every iteration after the first one.
> 
> (0..3).map { |n| n % 2 == 0 ? 1 : -1 }.each { |n| puts n }
> 
> You could of course just use each by itself:
> 
> (0..3).each do |n|
>  if n % 2 == 0
>    puts 1
>  else
>    puts -1
>  end
> end