From: David Jacobs <developer@...>
Date: 2011-02-24T07:12:33+09:00
Subject: Re: finding a tag in a binary file

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Hi Rob,

I don't usually work with binary files, but I would imagine you could do
something like this (untested):

search_byte = 0b00100010
contents = File.binread('1DICOMDIR').bytes.to_a
index = contents.index(search_byte)

# I assume you want the next entry after
name = contents[index.next]

Then simply decode the name however is appropriate.

David

On Wed, Feb 23, 2011 at 4:28 PM, rob s. <rsnotnats@gmail.com> wrote:

> Hi I'm a complete non programmer but willing to give it a try.
>
> I have a DICOMDIR (medical imaging file) which has various tags in,
> following a tag ie 0010, 0010 is the "patient name", "study date"
> 0008,0020 is another.
>
> I have several DICOMDIR and I would like to extract just a few bits of
> information from them to a .txt file, the files average size is about
> 343 KB as its full of other information as well which I don't need. Each
> file has amongst other things a list of about 10 names, scan dates etc.
>
> So far I've managed to read the file into an array using
>
> contentsArray=[]    #open new array empty
>
> open('1DICOMDIR', 'rb') { |f| f.each_byte { |f| contentsArray.push f } }
>
> This gets the info into an array
>
> although its a hex file it displays the contents in decimal, but they
> correspond to the hex codes I've seen in a hex editor...
>
> My problem is I don't know how to detect 0010,0010 ? then extract the
> name. Can anyone help, I've looked all over the web but not finding
> anything to help me much. Thanks a lot
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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