From: Robert Klemme <shortcutter@...>
Date: 2011-02-15T19:04:05+09:00
Subject: Re: Hash sanitization from query - newbie

On Tue, Feb 15, 2011 at 10:51 AM, Sem Ptiri <rubyforum@chthonic.co.za> wrote:
> If I have the following:
>
> [[148,"Uneducated"],[135,"Highschool"],[272,"Some
> college"],[141,"University"],[143,"Post-grad"],[144,"PhD"],[141,"other"],[8,"Post-doc"]]
>
> is there an function to invert/swap the numbers with strings?

irb(main):001:0> [[148,"Uneducated"],[135,"Highschool"],[272,"Some
irb(main):002:2"
college"],[141,"University"],[143,"Post-grad"],[144,"PhD"],[141,"other"],[8,"Post-doc"]].each
{|a| a.reverse!}
=> [["Uneducated", 148], ["Highschool", 135], ["Some\ncollege", 272],
["University", 141], ["Post-grad", 143], ["PhD", 144], ["other", 141],
["Post-doc", 8]]

Btw, for your original problem there is an elegant solution which has
not been shown yet:

irb(main):003:0> [{0=>"BSD", 1=>105, "Operating System"=>"BSD",
"count(*)"=>105},
irb(main):004:1* {0=>"SUSE", 1=>99, "Operating System"=>"SUSE", "count(*)"=>99},
irb(main):005:1* {0=>"Ubuntu", 1=>97, "Operating System"=>"Ubuntu",
"count(*)"=>97},
irb(main):006:1* {0=>"Unix", 1=>190, "Operating System"=>"Unix",
"count(*)"=>190},
irb(main):007:1* {0=>"Windows XP", 1=>92, "Operating System"=>"Windows XP",
irb(main):008:2* "count(*)"=>92}].each {|h| h.delete_if {|k,| Integer === k}}
=> [{"Operating System"=>"BSD", "count(*)"=>105}, {"Operating
System"=>"SUSE", "count(*)"=>99}, {"Operating System"=>"Ubuntu",
"count(*)"=>97}, {"Operating System"=>"Unix", "count(*)"=>190},
{"Operating System"=>"Windows XP", "count(*)"=>92}]

Although you have to consider that this works only if you do not have
numeric keys that you want to keep.

Cheers

robert

-- 
remember.guy do |as, often| as.you_can - without end
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