From: Brian Candler <b.candler@...>
Date: 2011-02-07T05:01:10+09:00
Subject: Re: pass the paramater?

Bigmac Turdsplash wrote in post #979843:
> mply=0
> kill=0
> open("list.lfi","rb").each do |block|
> ['lol', '%00'].each do |suffix|
>   while mply < 10
>       if block.include? ".log"
>         puts suffix
>         suffix
>         kill=1
>   break
>   print("!!! Check your log.html !!!")
>       end
>         if kill==1; break;end
>         mply=mply+1
>     end
>       if kill==1; break;end
>       mply=0
>   end
>     if kill==1; break;end
> end
>
> print suffix.last
>
>
>
> i always do things the hard way... i dont know how to get suffix out
> side of the loop...

If a local variable is first assigned to inside of a block, then its 
scope does not extend outside of the block (i.e. it's local to that 
block).

So you can assign to it outside the block:

  foo = nil
  10.times do |x|
    foo = x
  end
  puts foo    # remembers value

However, in this case 'suffix' is itself a block argument. In ruby 1.9, 
it's forced to be local to that block. In ruby 1.8 the block argument 
can be a variable which has already been assigned to, but that's bad 
practice.

suffix = nil
['lol', '%00'].each do |suffix
  ... do stuff
end
puts suffix   # doesn't work in ruby 1.9

So if you want the value of 'suffix' used in the last iteration of the 
loop, simply remember it explicitly.

last_suffix = nil
['lol', '%00'].each do |suffix|
  last_suffix = suffix
  ... do stuff
end
puts last_suffix

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