From: Michael Campbell <michael_s_campbell@...>
Date: 2002-04-09T01:34:18+09:00
Subject: Re: ruby-dev summary (Shared subpattern)


--- ts <decoux@moulon.inra.fr> wrote:
> >>>>> "M" == Michael Campbell <michael_s_campbell@yahoo.com>
> writes:
> 
> >> /(ab*c+d)XXX(?*1)/
> 
> M> This looks to me like a simple back-reference, no?
> 
> M> i.e.: /(ab*c+d)XXX(\1)/
> 
>  No, 
> 
>     \1 is the string matched by the 1st ()
>     (?*1) is the *pattern* given in ()
> 
>  The goal, if I've well understood, is to have shared pattern,
>  i.e. internally the pattern will *not* be duplicated

Of course you're 100% correct; I realize my mis-thinking here now.

(ab*)X(?*1)  will match:

aXba, aXa, abXabbbb, etc.

Thanks.

=====
--
Yahoo IM: michael_s_campbell

__________________________________________________
Do You Yahoo!?
Yahoo! Tax Center - online filing with TurboTax
http://taxes.yahoo.com/