From: ts Date: 2002-04-09T00:16:18+09:00 Subject: Re: ruby-dev summary (Shared subpattern) >>>>> "M" == Michael Campbell writes: >> /ab*c+dab*c+d/ == /(ab*c+d)(?*1)/ M> This is interesting. How does the above differ from: M> /(ab*c+d){2}/ ? a better example /(ab*c+d)XXX(?*1)/ Guy Decoux