From: Masaomi Hatakeyama <mhatakeyama@...>
Date: 2010-12-29T16:54:31+09:00
Subject: Re: convert String "1;2;3;4;5;" to Array

How about this?

eval("[" + "1;2;3".gsub(/;/,',') + "]")
=> [1,2,3]

Masa

2010/12/29 Adam Prescott <mentionuse@gmail.com>:
> I would avoid the inject solution because it's cumbersome and isn't as easy
> to understand; map is pretty much to-the-point and doesn't have this weird
> empty-array accumulator. The inject solution is just reinventing the map
> wheel.
>
> On Tue, Dec 28, 2010 at 6:43 PM, Ian M. Asaff <ian.asaff@gmail.com> wrote:
>
>> Yep.
>>
>> --sent from myu droid. typoos courtesy of droid's crappy keyboarsd
>> On Dec 28, 2010 6:41 PM, "Thomas T." <tthackery@gmail.com> wrote:
>> > Ian M. Asaff wrote in post #971169:
>> >> you mean something like this?
>> >> "1;2;3;4;5;6;7;8;9;10".split(';').inject([]) { |a,i| a << i.to_i }
>> >> => [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
>> >
>> > Ok, I've read the page on .inject, but do have a question on your
>> > solution. I'm interested in the [] where I read an initial value may be
>> > supplied in .inject([]). Is the [] initializing an empty array to which
>> > the accumulator, a, will populate?
>> >
>> > --
>> > Posted via http://www.ruby-forum.com/.
>> >
>>
>