From: "Rajesh M." <munikur@...>
Date: 2010-12-14T22:32:55+09:00
Subject: Grep a string

Hi list,

I need to grep the entire string "sync; sync; reboot" after 0 10 * * 0
in crontab -l and store it in a variable, that string is different on
different systems.



crontab -l |egrep -i "(sync|reb|shut)"

0 10 * * 0 sync; sync; reboot <---- regex should look for only sync;
sync; reboot

cd /var/log
grep "sync; sync; reboot" cron* |head -1
cron:Dec 12 10:00:00 hostname CROND[14898]: (root) CMD (sync; sync;
reboot)

Regular expression should find any string without the digitals (0 10 * *
0)

For example in another system if the crontab entry is like:
0 6 * * 0 shutdown -y -g0 -i6
regular expression should only look for the string after digitals 0 6 *
* 0, here it should look for shutdown -y -g0 -i6


Please help.
Thanks in advance

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