From: botp <botpena@...>
Date: 2010-10-30T12:30:45+09:00
Subject: Re: operator bug (or not)?

On Sat, Oct 30, 2010 at 1:29 AM, Robert Pankowecki
<robert.pankowecki@gmail.com> wrote:
> What's your point ?
> I know that [*a] == a when a.is_?(Array). It's logical.

of course LOL.  forgot to affix the object_id.. i should have pasted
your code but was getting lazy that night...

so..

> a=[]
=> []
>> (b=[*a]).object_id  == (b=*a).object_id
=> true

wc means, the [ ] is ignored

>> (b=*a).object_id  == (b=a).object_id
=> true

so is *

>> (b=[*a]).object_id  == (b=a).object_id
=> true

so is [* ]

> When you see such code:
> [*a]
>do you think a new array will be created ?
>Because I do.

the confusion is understandable. suffice it to say that the splat
cannot override literals or hell breaks loose :)

>> (b=[*[]]).object_id  == (b=*[]).object_id
=> false

and splat does not even have a corresponding alias or method :)

lesson is: do not compare splatted objects.. it's undocumented and
very confusing :))

best regards -botp