From: Robert Klemme <shortcutter@...>
Date: 2010-10-27T00:45:13+09:00
Subject: Re: Change captured values in a regexp

On 26.10.2010 15:47, Bruno Sousa wrote:
> Supposing there is a string like this:
> Oct 22 06:25:35 machine kernel: [271182.956004] IN= OUT=eth0
> SRC=10.8.0.248 DST=192.5.5.241
>
> I am using the following regexp to capture time:
> /Oct (\d{2}) (\d{2}:\d{2}:\d{2})/
>
> How can I alter the hour value only and keep it in the result returned?
> I want to decrease 3 hours.
> Instead of #<MatchData "Oct 22 06:25:35" 1:"22" 2:"06:25:35">
> It should return  #<MatchData "Oct 22 06:25:35" 1:"22" 2:"03:25:35">

You don't want to mess with what the regexp match returns.  Rather you 
need to process results afterwards.  And please also consider the other 
comments.

Kind regards

	robert

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