From: salamond <jarodzz@...>
Date: 2010-10-21T23:42:16+09:00
Subject: Re: about handling args in block

Let's see if I get this.
While I'm passing @left_node, and @right_node into this block,
I'm passing the reference of these 2 objects into a block.
Inside block, I can use these 2 references to modify the objects,
but I can't change the reference themselves.

Now here comes an update, is there a way to have the class destroy itself?

like
class Node
#snip
    def destroy
        self = nil
    end
end

[@left_node, @right_node].each do |node|
    node.destroy
end

Is it possible to have something like this work?
When I try this, it said can't change the value of self.


On Thu, Oct 21, 2010 at 7:09 PM, Robert Klemme
<shortcutter@googlemail.com> wrote:
> Please do not top post.
>
> On Thu, Oct 21, 2010 at 12:38 PM, salamond <jarodzz@gmail.com> wrote:
>
>> I wanner do this because this tree may not be a binary tree.
>> What if a node could link to a dozen nodes.
>
> In that case you would have a single collection (e.g. an Array) which
> stores child nodes!  For that use Jesus's solution.
>
>> we have to something like this.
>> nodes.each do |node|
>>  node = nil
>> end
>
> This won't work because you only assign to the block parameter and
> leave "nodes" unchanged.
>
> Cheers
>
> robert
>
> --
> remember.guy do |as, often| as.you_can - without end
> http://blog.rubybestpractices.com/
>
>