From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2010-10-16T18:08:01+09:00
Subject: Re: Most elegant way: array of files from array of directories

On Sat, Oct 16, 2010 at 6:50 AM, Terry Michaels <spare@frigidcode.com> wrote:
> I have a array of directories passed into my program. I want a new array
> which is a list of all files in said directories (only one level deep is
> necessary). N.B.:
>
> 1. Each elements of the new array must be an absolute (full) path, or at
> least relative to the cwd. (Assume all directories provided are also
> absolute or relative to cwd)
> 2. OS and preference agnostic: Especially, I do not know what directory
> separator will be used (say, backward- or forward-slash) or whether
> there will be a trailing directory separator in the directory path (say,
> a trailing forward-slash).
>
> Dir.foreach almost does what I want, but gives relative output instead
> of absolute.
>
> array_of_file_paths = Array.new
>
> array_of_directory_paths.each do |directory_path|
>  # ???
> end
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

Probably not the most elegant way, but this can give you some ideas:

irb(main):032:0> Dir["*"].each do |f|
irb(main):033:1* next if test ?f,f        # skip the files
irb(main):034:1> puts Dir["#{f}/*"].map {|x| File.expand_path(x)}
irb(main):035:1> end

You can loop around this collecting the subarrays and then flatten.

Jesus.