From: Dhruva Sagar <dhruva.sagar@...>
Date: 2010-10-16T17:33:21+09:00
Subject: Re: Is this an executable code?

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Hi,

well that is the syntax for using the method 'local'. The syntax mentioned
in the book is showing you how to use the method and what the arguments you
are supposed to pass to it in order to achieve what you have to. In place of
the arguments you have to put in real values when you are actually using the
method. You could assign those values to variables and then pass those
variables to the method. When you just type that in IRB, when it interprets
the call, it tries to resolve the values like 'year', 'month' etc. Since
they have not been defined, it outputs the error that the local variable
hasn't been defined.

in IRB if you did :

irb> year = '2009'
irb> month = '01'
.
.
.
irb> Time.local(year, month....)

then it will work as you'd expect it to again.

PS : If you do not have programming background, I suggest you go through a
book targetting beginners like yourself and get a hold of the basics of ruby
programming.

--
Thanks & Regards,
Dhruva Sagar.



On Sat, Oct 16, 2010 at 13:41, Kaye Ng <sbstn26@yahoo.com> wrote:

> I think I get it now.  I typed Time.local(2010,10,16,15,50,33)
> and IRB returned with values of year, month, day, hour, min, and sec in
> that order, with the values of the arguments passed to 'local'.
>
> But the code sample from the book I'm reading has the msec argument.
> Time.local(year, month, day, hour, min, sec, msec)
> I added another argument for the msec position but IRB returned with the
> same result as the previous, as if I didn't add the msec argument in
> there.   Why is that?
>
>
> Sorry, beginner here and no background in programming whatsoever.
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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