From: Ruwan Budha <ruwanb@...>
Date: 2010-09-18T04:50:35+09:00
Subject: Re: ruby regexpresion

Jeremy thanks so much for your help......it works.

could you please explain further how %r{(\(.*\)).*/(.*)'..(.*)}

captures the 3 interested part from the string......

I know you have explained but if you could kindly explain more with an 
easy way I think it will help me to learn....

thanks again


Jeremy Bopp wrote:
> On 9/17/2010 1:39 PM, Ruwan Budha wrote:
>> 
>> (21:15:32:873), xyz, pid 11560
>> 
>> 
>> I am stuck and I would appreciate if someone could give me some help. I
>> am newbie to ruby....thanks
> 
> The following example will work for your singular example, but it's
> likely that it won't work for your most general case since it assumes a
> fair bit about the contents of the lines to parse.  You'll need to read
> up on regular expressions in general if you need to edit this.
> Fortunately, there are plenty of decent references online:
> 
> http://www.regular-expressions.info/ruby.html
> http://www.tutorialspoint.com/ruby/ruby_regular_expressions.htm
> http://www.zenspider.com/Languages/Ruby/QuickRef.html#12
> or just google for ruby regexp. :-)
> 
> 
> Example:
> 
> # Assume str holds the string you want to parse.
> str = ....
> 
> str =~ %r{(\(.*\)).*/(.*)'..(.*)}
> puts [$1, $2, $3].join(', ')
> 
> 
> This regexp uses the parenthesis around the first field of interest as
> the first marker and captures the text within and including the
> parenthesis.  Then it chews up everything following that until the last
> /, which is the second marker.  It captures the following text until the
> ', the fourth marker.  Finally it throws away the next 2 characters and
> captures the rest of the string.
> 
> It has captured 3 matches which become available in the special
> variables $1, $2, and $3 based on the order in which they were matched
> in the string.  For convenience, those are put into an array, joined
> with ', ', and then printed out.
> 
> HTH. :-)
> 
> -Jeremy

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