From: John Smith <edvelez.g@...>
Date: 2010-09-17T23:32:15+09:00
Subject: Printing part what's found with a regex

Hi everyone,

I'm trying to build a program that filters
certain lines through regular expressions.
In the seconde regular expression I wan to
be able to print only what's within the
\(\w+\) part of the expression?

How do I do this?

counter = 0
if  inFile.nil? == false
  File.foreach(inFile) do |line|
    if line =~ /^[^%\s*^%]/
      if line =~ /(?!%)\w+\s+\(\w+\)/
        puts "found in line #{counter+1} "
        puts line
      end
    end
    counter = counter + 1
  end
end

Regards,
Ted.
-- 
Posted via http://www.ruby-forum.com/.