From: John W Higgins <wishdev@...>
Date: 2010-09-16T05:39:34+09:00
Subject: Re: access super from yield block?

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Afternoon,

On Wed, Sep 15, 2010 at 1:12 PM, Gene Angelo <web.gma@gmail.com> wrote:

> > What exactly are trying to achieve?
>
> I have class A that derives from class B
>
> A#parse and A#parse! override members of the same name in B
>
> A#parse and A#parse! both call A#do_parse to retrieve arguments from the
> command line in a loop. A yield in A#do_parse returns the arguments
> (argv). I want to call 'super argv' from both A#parse and A#parse! but
> super is not set to A#super.
>
>

How about something like this - a little hokey but it works

class A
  def x(parm)
    puts "Hi from A - #{parm}"
  end
end

class B < A
  alias :super_x :x

  def x(parm)
    puts "Hi from B - #{parm}"
    do_something { |z| super_x(z) }
  end

  def do_something
    yield "Hello"
  end
end

The alias will in essence give you the super method so you can use it inside
the block.

John

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