From: Adam Prescott <mentionuse@...>
Date: 2010-09-15T05:41:30+09:00
Subject: Re: Iterate over a cartesian product.

Whoops, that should be ary.first.product, of course.

On Tue, Sep 14, 2010 at 9:40 PM, Adam Prescott <mentionuse@gmail.com> wrote:
> ary.first is the first element of ary.
> ary.product(one, two, ...) is the cartesian product of ary with its arguments.
> ary.drop(1) is ary[1..-1], all the elements of ary but the first.
> ary.product(*ary.drop(1)) passes each element of ary[1..-1] to
> product() as an argument, making it equivalent to
>
> ary.product(ary[1], ary[2], ..., ary[-1])
>
>>
>> That looks so cool I wish I knew what it does.
>>
>>
>