From: Vadivelan Vatti <vattibe@...>
Date: 2010-09-07T16:01:03+09:00
Subject: Re: Dice Roller

David A. Black wrote:
> Hi --
> 
> On Tue, 7 Sep 2010, Phlip wrote:
> 
>>> get a zero?
>> while x <= roll.to_i
>> puts "Roll " + x.to_s + ": " + rand(max=6).to_s
>> end
>>
>> Take out the gets.chomp:
>>
>> roll = '12' # gets.chomp
>>
>> that lets you work on the loop without entering over and over again.
> 
> That changes the behavior of the program pretty significantly, though.
> 
>> then either fix your while loop by incrementing: x += 1
>>
>> or use an each loop (which is truly the Ruby way):
>>
>>  (0...roll.to_i).each do |x|
>>     puts 'etc'
>>   end
> 
> I'd be inclined to use #times:
> 
>    print "How many dice do you want to roll? "
>    num_rolls = gets.to_i
>    num_rolls.times do |n|
>      puts "Roll #{n+1}: #{rand(6) + 1}"
>    end
> 
> 
> David
> 
> --
> David A. Black, Senior Developer, Cyrus Innovation Inc.
> 
>    The                   Ruby training with Black/Brown/McAnally
>    Compleat              Philadelphia, PA, October 1-2, 2010
>    Rubyist               http://www.compleatrubyist.com

Hi,

I have made a small change, but both will returns the same result..

By adding the min value to the rand(max-min), we can get random number 
bw the range(min,max).

print "How many dice do you want to roll? "
num_rolls = gets.to_i
num_rolls.times do |n|
  puts "Roll #{n+1}: #{1 + rand(6-1)}"
end

Thanks,
Vaddi
-- 
Posted via http://www.ruby-forum.com/.