From: Robert Klemme <shortcutter@...>
Date: 2010-09-07T15:30:09+09:00
Subject: Re: how to write this  xpath?

On 07.09.2010 07:07, Pen Ttt wrote:
> there is an html file
> <table>
> <tr>
> <td>ok
> <strong>Sep 10</strong>
> |<a href="ttt">Oct 10</a>
> |<a href="kkk">Dec 10</a>
> <table>
> <tr>
> <td>
> 123
> </td>
> <td>
> 567
> </td>
> </tr>
> </table>
> </td>
> </tr>
> </table>
> when i open it with firefox,the output is :
> ok Sep 10 | Oct 10 | Dec 10
> 123   567
> what i want to get is
> ok Sep 10 | Oct 10 | Dec 10
> here is my codes
> require 'rubygems'
> require 'nokogiri'
> web='/home/test'
> doc = Nokogiri::HTML.parse(open(web))
> data=doc.xpath('/html/body/table/tr/td')
> puts data
> i get
> <td>ok
> <strong>Sep 10</strong>
> |<a href="ttt">Oct 10</a>
> |<a href="kkk">Dec 10</a>
> <table><tr>
> <td>
> 123
> </td>
> <td>
> 567
> </td>
> </tr></table>
> </td>
> how can i get :
> ok
> <strong>Sep 10</strong>
> |<a href="ttt">Oct 10</a>
> |<a href="kkk">Dec 10</a>

You want the first row?  Try

'/html/body/table/tr[1]/td'

See also
http://www.zvon.org/xxl/XPathTutorial/General/examples.html
http://www.w3schools.com/xpath/

Cheers

	robert

-- 
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/