From: "Savard, Joseph" <Joseph.Savard@...>
Date: 2010-09-03T21:22:15+09:00
Subject: Re: p vs. print

@Alex & @Ali The correct explanation is P is effectively puts x.inspect

Notice in the script I sent Ali I used inspect I in the printing of ary1 when using puts.

[-------------------------]
require "rubygems"
require "narray"

ary1 = NArray.sfloat(3,4)
puts "---puts ary1.inspect produces"
puts ary1.inspect
puts "---p ary1 produces"
p ary1
puts "---puts ary1 produces"
puts ary1
puts "---"

[------------------------]

produces:
---puts ary1.inspect produces
NArray.sfloat(3,4):
[ [ 0.0, 0.0, 0.0 ],
  [ 0.0, 0.0, 0.0 ],
  [ 0.0, 0.0, 0.0 ],
  [ 0.0, 0.0, 0.0 ] ]
---p ary1 produces
NArray.sfloat(3,4):
[ [ 0.0, 0.0, 0.0 ],
  [ 0.0, 0.0, 0.0 ],
  [ 0.0, 0.0, 0.0 ],
  [ 0.0, 0.0, 0.0 ] ]
---puts ary1 produces

---

________________________________
From: Alex Stahl <astahl@hi5.com>
Reply-To: <ruby-talk@ruby-lang.org>
Date: Thu, 2 Sep 2010 14:23:57 -0500
To: ruby-talk ML <ruby-talk@ruby-lang.org>
Subject: Re: p vs. print

Ruby uses "puts", not "print".  "p" is short for "puts".

Try this:

puts ary1

You'll get the same results as:

p ary1


On Thu, 2010-09-02 at 14:16 -0500, Abder-Rahman Ali wrote:
> I wrote the following scripts from section (2) here:
> http://ruby.gfd-dennou.org/tutorial/gokuraku/index-e.html
>
> require "rubygems" # Not in the example
> require "narray"
> ary1 = NArray.sfloat(3,4)
>
> When I tried to display the result using
>
> print ary1
>
> It did NOT show anything.
>
> While when I used:
>
> p ary1
>
> I got the result displayed?
>
> Why is that?
>
> Thanks.