From: Harry Kakueki Date: 2010-08-29T23:26:07+09:00 Subject: Re: delete char On Sun, Aug 29, 2010 at 9:56 PM, Pen Ttt wrote: > pt@pt-laptop:~$ irb > irb(main):001:0>  'gkhj*&()'[0] > => 103 > irb(main):002:0> > > can i get  'gkhj*&()'[0]=>g?? > > > -- > Posted via http://www.ruby-forum.com/. > > p 'gkhj*&()'[0] #Ruby 1.9 p 'gkhj*&()'.split(//)[0] #Ruby 1.8 ?? Harry