From: skim Date: 2010-08-02T11:56:33+09:00 Subject: Re: Lazy array --00163645840e0eaa28048cce5966 Content-Type: text/plain; charset=ISO-8859-1 Ruby Arrays dynamically expand as needed. You can apply blocks to them to return things like even numbers. array = [] array.size # => 0 array[0] # => nil array[9999] # => nil array << 1 array.size # => 1 array << 2 << 3 << 4 array.size # => 4 array = (0..9).to_a array.select do |e| e % 2 == 0 end # => [0,2,4,6,8] Does this help? On Sun, Aug 1, 2010 at 17:45, Andrew Wagner wrote: > How can I get a lazy array in Ruby? E.g., in Haskell, I can talk about > [1..], which is an infinite list, lazily generated as needed. I can also do > things like "iterate (+2) 0", which applies whatever function I give it to > generate a lazy list. In this case, it would give me all even numbers. > Anyway, I'm sure I can do such things in Ruby, but can't seem to work out > how. > --00163645840e0eaa28048cce5966--