From: Josh Cheek <josh.cheek@...>
Date: 2010-07-26T06:11:40+09:00
Subject: Re: syntax

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On Sun, Jul 25, 2010 at 7:41 AM, Raghu Maddali <raghu1216@yahoo.co.in>wrote:

> I apologize for miscommunication.I know that Ruby will not have any
> pointers and I guess its a variable declared with private access
> modifier.Its like
>
> private $config;
> $this->config = parse_ini_file('conf/Voyager.ini', true);
>
> So,how would you code this in Ruby?Is that the same
>
> private $config
> $self.config=parse_ini_file(....)???
>
> Raghu
>
> > presumably you want self.config = parse_ini_file(...) your actual
> > question
> > is a little unclear (I assume you meant to refer to a different
> > language)
> > but you should note that there are no pointers in Ruby, and in the
> > preceeding example, "config=" is a method defined on self, you are not
> > directly setting an instance variable like you would be in Java, but
> > rather
> > invoking a method which probably sets an instance variable, though not
> > necessarily.
>
> --
> Posted via http://www.ruby-forum.com/.
>
>
In Ruiby, all instance variables are private (hence the need to use the
#config= method)

From within an object, you can access its private instance variables
directly by suing the @ sigil

@config = parse_ini_file(...)

from outside the object, you must use a method.


class Person
  def name=(newname)
    @name = newname
  end
  def name
    @name
  end
end

person = Person.new

# invoke the #name= method, which will set @name
person.name = 'Josh'

# invoke the #name method, which will get @name
person.name # => "Josh"

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