From: Raghu Maddali <raghu1216@...>
Date: 2010-07-25T21:41:28+09:00
Subject: Re: syntax

I apologize for miscommunication.I know that Ruby will not have any 
pointers and I guess its a variable declared with private access 
modifier.Its like

private $config;
$this->config = parse_ini_file('conf/Voyager.ini', true);

So,how would you code this in Ruby?Is that the same

private $config
$self.config=parse_ini_file(....)???

Raghu

> presumably you want self.config = parse_ini_file(...) your actual 
> question
> is a little unclear (I assume you meant to refer to a different 
> language)
> but you should note that there are no pointers in Ruby, and in the
> preceeding example, "config=" is a method defined on self, you are not
> directly setting an instance variable like you would be in Java, but 
> rather
> invoking a method which probably sets an instance variable, though not
> necessarily.

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