From: James O'Brien <jeob32@...>
Date: 2010-07-14T09:18:31+09:00
Subject: Re: How can I get the result of this equation

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more conclusively (using =)

array = [10,20,30]
array.each {|number| number = (number * 10)}
puts array

> [10,20,30]
i.e. not [100,200,300]!

On Wed, Jul 14, 2010 at 1:12 AM, James O'Brien <jeob32@gmail.com> wrote:

> Ali,
>
> I suspect the example you're trying was actually printing out
> value*s*(...s! plural NOT value)
>
> this would then make sense as a demonstration that the 'each' loop did not
> alter the array
>
> :)
>
>
> On Wed, Jul 14, 2010 at 12:26 AM, Abder-Rahman Ali <
> abder.rahman.ali@gmail.com> wrote:
>
> > I have written this a script like this:
> >
> > values = [10, 20, 30].each {|value| value + (value * 10)}
> >
> > puts value
> >
> > In this case, I get:
> > undefined local variable or method `value' for main:Object (NameError)
> >
> > I'm trying to see the result of the equation value + (value * 10)
> >
> > What should I do?
> >
> > Thanks.
> > --
> > Posted via http://www.ruby-forum.com/.
> >
> >
>

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