From: Rolf Pedersen <rolfhsp@...>
Date: 2010-07-05T20:52:57+09:00
Subject: Re: File data extraction

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Thanks Brian, that helped me a lot ! :o)

The code now looks like this:

filenames = File.open(filename).readlines.join.scan(/^@begin
Objects\n(.*?)^@end;/m)[0][0].split("\n").map{|l| l.scan(/"(.*?)"/)[0][0]}
Probably far from optimal, but it seems to do the trick.

Best regards,
Rolf

On Mon, Jul 5, 2010 at 12:12 PM, Brian Candler <b.candler@pobox.com> wrote:

> Rolf Pedersen wrote:
> > My initial idea was to treat the whole thing as one long string, and
> > extract
> > the part within the being-end-block by using regexp, converting the
> > result
> > back to individual lines (split '\n') and doing array.map and regexp to
> > single out the name in the first quote on each line.
> > But I keep hitting the wall, especially with the first step in this
> > approach... :o(
>
> How about this for starters:
>
> p src.scan(/^@begin(.*?)^@end;/m)
> --
> Posted via http://www.ruby-forum.com/.
>
>

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