From: Andy Bogdanov <andy.bogdanov@...>
Date: 2010-06-28T21:52:13+09:00
Subject: passing a block to yield

Hello

I was trying to make an iterator that goes through a simple tree
structure something like that:

class Node
...
def each_child(&block)
  @children.each { |child| yield(child) { child.each_child(&block) } }
end
...
end

so i could generate a simple html menu:

puts "<ul>"
root_node.each_child { |node|
  puts "<li><a href=\"#{child.link}\">#{child.title}</a></li>"
  unless node.children.empty?
    puts "<ul>"
    yield
    puts "</ul>"
  end
}
puts "</ul>"

But it turns out that Ruby syntax prohibits passing blocks to yield. A
simple workaround is to use block.call instead of yield everywhere.

Is there any good reason for that limitation?
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