From: Martin Hansen <mail@...>
Date: 2010-06-21T21:48:02+09:00
Subject: Re: How to print exit status to a log file?

> It seems there is a much simpler solution to what you want - you don't
> even need a signal handler for this:
> 
> $ ruby19 -e 'begin; sleep 60; rescue Exception => e; p e.class, e,
> e.backtrace; end' &
> [1] 2664
> $ echo $!
> 2664
> $ kill -INT $!
> $ Interrupt
> Interrupt
> ["-e:1:in `sleep'", "-e:1:in `<main>'"]
> [1]+  Done                    ruby19 -e 'begin; sleep 60; rescue
> Exception => e; p e.class, e, e.backtrace; end'
> 

That indeed looks very clever. But I note that if the script is 
terminated I get "SignalException" and not "Terminated". Also, I note 
that backtrace is a list, and I was wondering what method Ruby normally 
uses to reformat and pretty print that (Ruby is not simply printing and 
indenting the lines).

However, I fail to see how this exception handling should be integrated 
in practice with my code that currently relies on an at_exit call (line 
84):

http://code.google.com/p/biopieces/source/browse/trunk/code_ruby/Maasha/lib/biopieces.rb

And just a reminder that I am trying to create super simplified scripts 
of this type:

http://pastie.org/1013476


Cheers,


Martin

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