From: Robert Klemme <shortcutter@...>
Date: 2010-06-12T18:00:04+09:00
Subject: Re: How can I call foo in Bar.foo ?

On 06/12/2010 07:33 AM, Ntys Dd wrote:
> it's like this
> ........................
> module Bar
>   def foo
>     puts 'hello'
>   end
>   def bye
>     puts 'bye'
>   end
> end
> 
> def Bar.foo
>   #Do something
>   #I want to call foo now
>   #And call bye
>   #...
> end
> ........................
> 
> is there anything i can to to solve the problem

It does not really make sense since the first #foo you define is an 
instance method while the latter is a class method.  When you have a 
class you do not have an instance available so on what instance would 
you intend to invoke #foo on?  It can only work the other way round: you 
have the instance method invoking the class (module) method.

module Bar
   def self.foo
     puts "module method"
   end

   def foo
     puts "instance method"
     Bar.foo
   end
end

irb(main):011:0> o = Object.new.extend Bar
=> #<Object:0x910a418>
irb(main):012:0> o.foo
instance method
module method
=> nil

Of course you can also do

module Bar
   def uber_foo
     foo
     bye
   end
end

Kind regards

	robert

-- 
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/